SSC Sample Paper Mock Test-8 SSC CGL Tear-II Paper-1

  • question_answer
    One of the diagonals of a square is the portion of the line \[x/2+y/3=2\]intercepted between the axes. Then, the extremities of the other diagonal are

    A)  \[(5,5),\] \[(-1,1)\]

    B)         \[(0,0),\]\[(4,6)\]

    C)  \[(0,0),\] \[(-1,1)\]

    D)  \[(5,5),\]\[(4,6)\]

    Correct Answer: A

    Solution :

    Extremities of the given diagonal are (4, 0) and (0, 6). Hence slope of this diagonal is \[-3/2\]and slope of other diagonal is 2/3. The equation of the other diagonal is
    \[\frac{x-2}{\frac{3}{\sqrt{3}}}=\frac{y-3}{\frac{2}{\sqrt{3}}}=r\]
    For the extremities of the diagonal, \[r=\pm \sqrt{13}.\]Hence,
    \[x-2=\pm \,\,3,\]\[y-3=\pm \,\,2\]
    \[x=5,-1\]and \[y=5,\]\[1\]
    Therefore, the extremities of the diagonal are (5, 5) and \[(-\,\,1,1).\]


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