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SSC Sample Paper Mock Test-8 SSC CGL Tear-II Paper-1

  • question_answer
    A student walks from his house at 2 - km/h and reaches his school late by 6 min. Next day, be increases his speed by 1 km/h and reaches 6 min before school time. How far is the school from his house?

    A)  \[\frac{5}{4}\text{km}\]

    B)  \[\frac{7}{4}\text{km}\]

    C)  \[\frac{9}{4}\text{km}\]

    D)  \[\frac{11}{4}\,\,\text{km}\]

    Correct Answer: B

    Solution :

    Let the required distance be x km. Then, \[\frac{x}{(5/2)}-\frac{x}{(7/2)}=\frac{12}{60}\] [\[\because \]Difference between two times is 12 min] \[\Rightarrow \]   \[\frac{2x}{5}-\frac{2x}{7}=\frac{1}{5}\] \[\Rightarrow \]   \[14x-10x=7\] \[\Rightarrow \]               \[4x=7\] \[\Rightarrow \]               \[x=\frac{7}{4}\] Required distance\[=\frac{7}{4}\,\,\text{km}\]


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