SSC Sample Paper Mock Test-9 SSC CGL Tear-II Paper-1

The diagonal of a square A is (a + b). The diagonal of a square whose area is twice the area of square A, is

A) \[2\,\,(a+b)\]

B) \[2\,\,{{(a+b)}^{2}}\]

C) \[\sqrt{2}\,\,(a+b)\]

D) \[\sqrt{2}\,\,(a-b)\]

Correct Answer: C

Solution :

Diagonal of square A = (a + b)

\[\sqrt{2}\,\,\text{side}\,\,\text{=}\,\,a+b\]

\[\text{side=}\left( \frac{a+b}{\sqrt{2}} \right)\]

Area of second square \[=2\times \]Area of square A

\[{{(\text{side})}^{2}}=2\times {{\left( \frac{a+b}{\sqrt{2}} \right)}^{2}}\]

\[=2\frac{{{(a+b)}^{2}}}{2}\]

\[{{(\text{side)}}^{2}}={{(a+b)}^{2}}\]

\[\Rightarrow \] \[\text{side}\]\[=(a+b)\]

Diagonal of second square\[=\sqrt{2}\,\,(\text{side)=}\sqrt{2}\,\,(a+b)\]