A) \[2\,\,(a+b)\]
B) \[2\,\,{{(a+b)}^{2}}\]
C) \[\sqrt{2}\,\,(a+b)\]
D) \[\sqrt{2}\,\,(a-b)\]
Correct Answer: C
Solution :
Diagonal of square A = (a + b) |
\[\sqrt{2}\,\,\text{side}\,\,\text{=}\,\,a+b\] |
\[\text{side=}\left( \frac{a+b}{\sqrt{2}} \right)\] |
Area of second square \[=2\times \]Area of square A |
\[{{(\text{side})}^{2}}=2\times {{\left( \frac{a+b}{\sqrt{2}} \right)}^{2}}\] |
\[=2\frac{{{(a+b)}^{2}}}{2}\] |
\[{{(\text{side)}}^{2}}={{(a+b)}^{2}}\] |
\[\Rightarrow \] \[\text{side}\]\[=(a+b)\] |
Diagonal of second square\[=\sqrt{2}\,\,(\text{side)=}\sqrt{2}\,\,(a+b)\] |
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