SSC Sample Paper Mock Test-9 SSC CGL Tear-II Paper-1

  • question_answer
    A circular wire of diameter 42 cm is folded in the shape of a rectangle whose sides are in the ratio 6 : 5. Find the area enclosed by the rectangle \[\left( \text{Take}\,\,\pi =\frac{22}{7} \right)\]

    A)  \[540\,\,\text{c}{{\text{m}}^{2}}\]

    B)  \[1080\,\,\text{c}{{\text{m}}^{2}}\]

    C)  \[2160\,\,\text{c}{{\text{m}}^{2}}\]

    D)  \[4320\,\,\text{c}{{\text{m}}^{2}}\]

    Correct Answer: B

    Solution :

    Radius of circular wire \[=\frac{42}{2}=21\,\,\text{cm}\]
    Circumference of wire
    \[=2\pi r=2\times \frac{22}{7}\times 21=132\,\,\text{cm}\]
    Let the length and breadth of rectangle be 6x and 5x, respectively.
    \[\therefore \] Perimeter of rectangle \[=2\,\,(6x+5x)=22x\]
    According to the question, \[22x=132\]
    \[\Rightarrow \]               \[x=\frac{132}{22}=6\]
    \[\therefore \] Length of rectangle \[=6x=6\times 6=36\,\,\text{cm}\]
    Breadth of rectangle \[=5x=5\times 6=30\,\,\text{cm}\]
    \[\therefore \] Area \[=36\times 30=1080\,\,\text{c}{{\text{m}}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner