A) 6
B) 18
C) 27
D) 36
Correct Answer: B
Solution :
Let fraction \[=\frac{2x}{3y}\] \[\therefore \] \[\frac{2x-6}{3y}=\frac{2x}{3y}\times \frac{2}{3}\] \[\Rightarrow \] \[(2x-6)\times 3=4x\] \[\Rightarrow \] \[x=9\] \[\therefore \] \[2x=2\times 9=18\]You need to login to perform this action.
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