A) \[\sqrt{3x}+y=4\]
B) \[x+\sqrt{3}y+4=0\]
C) \[x+\sqrt{3}y=4\]
D) None of the above
Correct Answer: C
Solution :
AB = 1 \[\Rightarrow \]\[C\equiv \,\,(2+1\times \cos 60{}^\circ ,1\times \sin 60{}^\circ )=\left( \frac{5}{2},\frac{\sqrt{3}}{2} \right)\] \[E\equiv \,\,(1,1\times \sin 60{}^\circ +1\times \sin 60{}^\circ )=(1,\sqrt{3})\] Therefore, the equation of CE is \[y-\sqrt{3}=\frac{\sqrt{3}-\frac{\sqrt{3}}{2}}{1-\frac{5}{2}}(x-1)\Rightarrow x+\sqrt{3}\,\,y=4\]You need to login to perform this action.
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