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SSC Sample Paper Mock Test-9 SSC CGL Tear-II Paper-1

  • question_answer
    The distance between two stations A and B is 450 km. A train starts at 4 pm from A and moves towards B at an average speed of 60 km/h. Another train starts from B at 3 : 20 pm and moves towards A at an average speed of 80 km/h. How far from A will the two trains meet and at what time?

    A) 2 h 50 min

    B)         2 h 25 min

    C)  2 h 10 min

    D)  2 h 40 min

    Correct Answer: A

    Solution :

    Suppose two trains meet at x km from A. [Time taken by B to cover \[(450-x)\] km] \[-\][Time taken by A to cover x km] \[=\frac{40}{60}\] \[\Rightarrow \]\[\frac{(450-x)}{80}-\frac{x}{60}=\frac{40}{60}\] \[\Rightarrow \]\[3\,\,(450-x)-4x=160\] \[\Rightarrow \]\[7x=1190\] \[\Rightarrow \]\[x=170\] Thus, the two trains meet at a distance of 170 km from A. Time taken by A to cover \[170\,\,\text{km}=\frac{170}{60}\text{h}=2\,\,\text{h}\]50 min. So, the two trains meet at 6 : 50 pm.


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