A) 75.5
B) 75.8
C) 76.0
D) 76. 8
Correct Answer: B
Solution :
Let total number of candidates = 100 \[\therefore \]Total marks of 40 candidates \[=40\times 74\] and total marks of 60 candidates \[=60\times 77\] Hence, required average marks \[=\frac{40\times 74+60\times 77}{100}\] \[=\frac{2960+4620}{100}=\frac{7580}{100}=75.80\]You need to login to perform this action.
You will be redirected in
3 sec