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NEET Sample Paper NEET Sample Test Paper-10

  • question_answer
             A wire of length L, Cross-sectional area A is made of a material of Young's modulas Y. The wire is stretched by an amount X, which lies well within the elastic limit. The work done(W) by the force is:

    A)  \[W=\frac{Y{{X}^{2}}}{{{L}^{2}}}\]                  

    B)  \[W=\frac{Y{{X}^{2}}}{2{{L}^{2}}}\]

    C)  \[W=\frac{1}{2}\frac{YA{{X}^{2}}}{{{L}^{2}}}\]  

    D)  \[W=\frac{YA{{X}^{2}}}{L}\]

    Correct Answer: C

    Solution :

    According to Hooke's law \[Y=\frac{Stress}{Strain}=\frac{F/A}{X/L}\] \[F=\left( \frac{YA}{L} \right)X\] \[W=\frac{1}{2}\] (Tension) (Extension) \[W=\frac{1}{2}\,\,\frac{YA\,{{X}^{2}}}{L}\]


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