A) \[5\Omega \]
B) \[5.6\Omega \]
C) \[6.76\Omega \]
D) \[20\Omega \]
Correct Answer: A
Solution :
Diode current \[=\frac{P}{V}=\frac{100\times {{10}^{-3}}}{0.5}=0.2A\] Potential differences across \[R=1.5-0.51V\] As, \[IR=V\] \[\Rightarrow \] \[R=\frac{1}{0.2}=5\Omega \]You need to login to perform this action.
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