A) \[[{{M}^{3}}L{{T}^{0}}]\]
B) \[[{{M}^{1/2}}{{L}^{3/2}}{{T}^{-2}}]\]
C) \[[{{M}^{0}}{{L}^{-7/2}}{{T}^{0}}]\]
D) \[[M{{L}^{7/2}}{{T}^{-2}}]\]
Correct Answer: B
Solution :
\[[\beta ]=L\] \[[M{{L}^{2}}{{T}^{-2}}]=\frac{\alpha {{[L]}^{1/2}}}{[L]}\] \[\alpha =[M]\,[{{L}^{5/2}}]\,[{{T}^{-2}}]\] \[\Rightarrow \] dimensions of \[(\alpha \times \beta )=[M{{L}^{5/2}}{{T}^{-2}}]\times (L)\] \[=[M{{L}^{7/2}}{{T}^{-2}}]\]You need to login to perform this action.
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