A) 2R
B) 3R
C) 4R
D) 5R
Correct Answer: C
Solution :
As time period \[T\alpha \,{{R}^{3}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{2}}{{\left( \frac{{{R}_{1}}}{{{R}_{2}}} \right)}^{3}}\] \[{{\left( \frac{T}{8T} \right)}^{2}}={{\left( \frac{R}{R} \right)}^{3}}\] \[R'=4R\]You need to login to perform this action.
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