A) \[\alpha \]
B) zero
C) \[C\left( \frac{\sqrt{3}-1}{2} \right)\]
D) \[C\left( \frac{\sqrt{3}+1}{2} \right)\]
Correct Answer: C
Solution :
As from the figure, \[\frac{1}{{{C}_{\infty }}}=\frac{1}{{{C}_{\infty }}+C}+\frac{2}{C}\] \[=\frac{3C+2{{C}_{\infty }}}{C({{C}_{\infty }}+C)}\] Here, circuit is splitted into two parts as shown in the figure, \[2C_{\infty }^{2}+2C{{C}_{\infty }}-{{C}^{2}}=0\] \[\Rightarrow \] \[{{C}_{\infty }}=C\left( \frac{-1+\sqrt{3}}{2} \right)\]You need to login to perform this action.
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