A) 1.2 K
B) 2.4 K
C) 4.8 K
D) 6.6 K
Correct Answer: B
Solution :
\[C=\frac{q}{m({{T}_{2}}-{{T}_{1}})}\] Given that \[C=75\,J\,{{K}^{-1}}\,mo{{l}^{-}},\] \[Q=1.0\,kJ=1000\,J\] \[75=\frac{1000}{5.55\times \Delta T}\left( m=\frac{1000}{18}=5.55 \right)\] \[\therefore \] \[\Delta T=\frac{1000}{5.55\times 75}=2.4\,K\]You need to login to perform this action.
You will be redirected in
3 sec