A) \[AB\,{{O}_{2}}\]
B) \[{{A}_{2}}B{{O}_{2}}\]
C) \[{{A}_{2}}{{B}_{3}}{{O}_{4}}\]
D) \[A{{B}_{2}}{{O}_{2}}\]
Correct Answer: D
Solution :
We know, in ccp If number of atoms = n Then number of octahedral voids = n and number of tetrahedral voids\[=2n\]\[\therefore \] | \[{{A}^{2+}}\] | \[{{B}^{+}}\] | \[{{O}^{2-}}\] |
\[n\times 2\times \frac{1}{4}\] | \[n\] | \[n\] | |
\[\frac{n}{2}\] | \[n\] | \[n\] | |
1 | 2 | 2 |
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