A) group 4
B) group 6
C) group 16
D) group 14
Correct Answer: D
Solution :
When IIA group element (Ra) loses one \[\alpha -\]particle its group no. decreases by two unit, i.e., go into zero group (group 16). But as it is radioactive due to successes emission, the last product obtained is Pb (group 14). \[{{\,}_{88}}R{{a}^{226}}\xrightarrow{{}}\,_{82}^{214}Pb+\,3_{2}^{4}He\]You need to login to perform this action.
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