A) 1
B) 1/3
C) 1/4
D) 1/2
Correct Answer: D
Solution :
\[\omega =\frac{2\pi }{T}=\frac{2\pi }{12}=\frac{\pi }{6}\frac{rad}{\sec }\] (For\[y=2\,cm\])\[2=4\left( \sin \frac{\pi }{6}{{t}_{1}} \right)\] By solving \[{{t}_{1}}=1\sec \]\[(For\,y=4\,cm){{t}_{2}}=3\sec \] So time taken by particle in going from 2 cm to extreme position is\[{{t}_{2}}-{{t}_{1}}=2\sec .\] Hence required ratio will be\[\frac{1}{2}.\]You need to login to perform this action.
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