(i) and |
(ii) \[C{{H}_{3}}-CH=C{{H}_{2}}\]gives |
A)
(i)and (ii) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
B)
(i)and (ii)\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]
C)
(i) and (ii)\[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
D)
(i) and (ii) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]
Correct Answer: A
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