A) \[V'=2V\]
B) \[V'>2V\]
C) \[V'>>2V\]
D) \[V'<2V\]
Correct Answer: D
Solution :
For conversion of galvanometer (of resistances) into voltmeter, a resistance R is connected in series \[\therefore \]\[{{i}_{g}}=\frac{V}{R+G}\]and \[{{i}_{g}}=\frac{V'}{2R+G}\] \[\Rightarrow \]\[\frac{V}{R+G}=\frac{V'}{2R+G}\] \[\Rightarrow \]\[\frac{V'}{V}=\frac{2R+G}{R+G}=\frac{2(R+G)-G}{(R+G)}\] \[=2-\frac{G}{(R+G)}\Rightarrow V'=2V-\frac{VG}{(R+G)}\Rightarrow V'<2V\]You need to login to perform this action.
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