A) 0.786
B) 0.478
C) 0.549
D) 0.200
Correct Answer: B
Solution :
\[P=P_{{{C}_{5}}{{H}_{12}}}^{o}\times {{X}_{{{C}_{5}}{{H}_{12}}}}+P_{{{C}_{16}}{{H}_{14}}}^{o}\times {{X}_{{{C}_{6}}{{H}_{14}}}};\] \[P=440\times \frac{1}{5}+120\times \frac{4}{5}=\frac{920}{5}=184\] \[{{y}_{{{C}_{5}}{{H}_{12}}}}=\frac{{{P}_{{{C}_{5}}{{H}_{12}}}}}{{{P}_{t}}}\] Now, \[{{Y}_{{{C}_{5}}{{H}_{12}}}}=\frac{88}{184}=0.478\]You need to login to perform this action.
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