A) 0.2 g
B) 0.4 g
C) 2 g
D) 4 g
Correct Answer: A
Solution :
\[g=\frac{4}{3}\pi GR\rho \]and \[g'=\frac{4}{3}\pi GR'\rho \] \[\therefore \]\[\frac{g'}{g}=\frac{R'}{R}=0.2\Rightarrow g'=0.2g\]You need to login to perform this action.
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