A) \[\sqrt{\frac{3}{4}gh}\]
B) \[\sqrt{\frac{4}{3}gh}\]
C) \[\sqrt{4\,gh}\]
D) \[\sqrt{2\,gh}\]
Correct Answer: B
Solution :
Applying principle of conservation of total mechanical energy \[mgh=\frac{1}{2}I\left( \frac{{{v}^{2}}}{{{R}^{2}}} \right)+\frac{1}{2}m{{v}^{2}}\] Velocity at the bottom \[v=\sqrt{\frac{4}{3}gh}\]You need to login to perform this action.
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