A) isopropyi bromide
B) 3-bromopropane
C) allyl bromide
D) n-propyl bromide
Correct Answer: D
Solution :
In the presence of peroxide, HBr adds on alkenes in anti-Markovnikov's way, thus \[{{H}_{3}}C-\underset{\Pr opene}{\mathop{CH}}\,=C{{H}_{2}}+HBr\xrightarrow{Peroxide}\] \[\underset{n-propyl\,bromide}{\mathop{{{H}_{3}}C-C{{H}_{2}}-C{{H}_{2}}-Br}}\,\] Kharasch observed that the addition of HBr to un- symmetrical alkene in the presence of organic per- oxides follows an opposite course to that suggested by Markovnikov. This is termed anti-Markovnikov or peroxide effect.
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