A) 333 Hz
B) 374 Hz
C) 385 Hz
D) 394 Hz
Correct Answer: B
Solution :
Minimum frequency will be heard, when whistle moves away from the listener. \[{{n}_{\min }}=n\left( \frac{v}{v+{{v}_{s}}} \right)\] where \[v=rw=0.5\times 10=1\,m/s\] \[\Rightarrow \] \[{{n}_{\min }}=385\left( \frac{340}{340+10} \right)=374\,Hz.\]You need to login to perform this action.
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