A) 200 K
B) 400 K
C) 600 K
D) 800 K
Correct Answer: B
Solution :
\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{500}{{{T}_{1}}}\Rightarrow \frac{500}{{{T}_{1}}}=\frac{1}{2}\] (i) \[\frac{60}{100}=1-\frac{T_{2}^{'}}{{{T}_{1}}}\Rightarrow \frac{T_{2}^{'}}{{{T}_{1}}}=\frac{2}{5}\] (ii) Dividing equation (i) by (ii), \[\frac{500}{T_{2}^{'}}=\frac{5}{4}\Rightarrow T_{2}^{'}=400\,K\]
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