A) \[\pi \]
B) \[2\pi \]
C) \[\sqrt{2}\pi \]
D) \[\sqrt{{{\pi }^{2}}+4}\]
Correct Answer: D
Solution :
Linear distance moved by wheel in half revolution\[=\pi r.\]Point\[{{P}_{1}}\]after half revolution reaches at\[{{P}_{2}}\] vertically 2 m above the ground. \[\therefore \]Displacement \[{{P}_{1}}{{P}_{2}}\] \[=\sqrt{{{\pi }^{2}}{{r}^{2}}+{{2}^{2}}}=\sqrt{{{\pi }^{4}}+4}\] \[[\because \,r=1\,m]\]You need to login to perform this action.
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