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NEET Sample Paper NEET Sample Test Paper-13

  • question_answer
    The mean free path of electrons in a metal is \[4\times {{10}^{-8}}m.\]The electric field which can give on an average 2 eV energy to an electron in the metal will be in unit of \[V{{m}^{-1}}\]

    A) \[8\times {{10}^{-7}}\]            

    B) \[5\times {{10}^{-11}}\]

    C) \[8\times {{10}^{-11}}\]                      

    D) \[5\times {{10}^{7}}\]  

    Correct Answer: D

    Solution :

     Energy\[=2eV\] \[e{{V}_{0}}=2eV\Rightarrow {{V}_{0}}=2\] Now, electric field \[E=\frac{2}{4\times {{10}^{-8}}}=0.5\times {{10}^{8}}\] Hence \[E=5\times {{10}^{7}}\,V{{m}^{-1}}\]


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