A) \[3.2\,\pi \mu V\]
B) \[4.8\,\pi \mu V\]
C) \[0.8\,\pi \mu V\]
D) \[1.6\,\pi \mu V\]
Correct Answer: A
Solution :
According to Faraday's second law of electro- magnetic induction, the induced emf is given by the rate of change of magnetic flux linked with the circuit. Here, B = 0.0 4 T and\[\frac{-dr}{dt}=2\,mm{{s}^{-1}}\] Induced emf, \[e-\frac{-d\phi }{dt}=\frac{-BdA}{dt}=-B\frac{d(\pi {{r}^{2}})}{dt}\] \[=-B\pi 2r\frac{dr}{dt}\] Now, r = 2 cm \[e=-0.04\times \pi \times 2\times 2\times {{10}^{-2}}\times 2\times {{10}^{-3}}\] \[=3.2\,\pi \mu V\]You need to login to perform this action.
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