A) 4870 Pa
B) 4.87 Pa
C) 0.00487 Pa
D) 0.33 Pa
Correct Answer: A
Solution :
\[\pi =CRT\] \[C=0.002\,\text{mol}\,\text{d}{{\text{m}}^{-3}}=\text{2}\,\text{mol}\,{{\text{m}}^{-3}}.\] \[R=8.314\,J\,{{K}^{-1}}\,mo{{l}^{-1}},T=293\,K.\] \[\pi =CRT=2\times 8.314\times 293=4872.004\,\text{Pa}\text{.}\] Hence, the correct option is [a].You need to login to perform this action.
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