A) 10 V
B) 5 V
C) 13V
D) 0 V
Correct Answer: C
Solution :
Base current\[={{i}_{b}}=\frac{5-0.7}{8.6}=0.5\,mA\Rightarrow \] Now, \[{{I}_{c}}=\beta {{I}_{b}}=100\times 0.5\,mA\] By using \[{{V}_{CE}}={{V}_{CC}}-{{I}_{C}}{{R}_{L}}=18-50\times {{10}^{-3}}\times 100=13V.\] Hence, the correction option is .You need to login to perform this action.
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