A) 0.0831 g
B) 1.50 g
C) 3.01 g
D) 12.0 g
Correct Answer: B
Solution :
6020 J is required to melt 18 g of ice at \[0{}^\circ C\]. 1 J would melt \[=\frac{18}{6020}g\]of ice at \[0{{\,}^{o}}C\] \[\approx 3\times {{10}^{-3}}g\] 500 J would melt \[=500\times 3\times {{10}^{-3}}g\]of ice at \[0{{\,}^{o}}C.\] Answer = 1.5 g. Hence, the correct option is [b].You need to login to perform this action.
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