A) \[\frac{Q_{1}^{'}}{{{Q}_{1}}}=\frac{K+1}{K}\]
B) \[\frac{Q_{2}^{'}}{{{Q}_{2}}}=\frac{K+1}{2}\]
C) \[\frac{Q_{2}^{'}}{{{Q}_{2}}}=\frac{K+1}{2K}\]
D) \[\frac{Q_{1}^{'}}{{{Q}_{1}}}=\frac{K}{2}\]
Correct Answer: C
Solution :
Let C be the capacity of each condenser without slab. \[\therefore \] When slab from capacitor 2 is removed, net capacity \[=C/2\therefore \,Q_{2}^{'}=Q_{2}^{'}=\frac{{{C}_{\varepsilon }}}{2}\] Before the slab is removed\[{{C}_{1}}=C\] and \[{{C}_{2}}=KC\] \[{{C}_{Net}}=\frac{KC}{K+1}\] \[{{Q}_{1}}={{Q}_{2}}=\frac{K{{C}_{\varepsilon }}}{K+1}\] \[\therefore \] \[\frac{Q_{2}^{'}}{{{Q}_{2}}}=\frac{{{C}_{\varepsilon }}(K+1)}{2(K{{C}_{\varepsilon }})}=\frac{K+1}{2K}.\] Hence, the correction option is [c].You need to login to perform this action.
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