A) \[\mu <\frac{1}{2}\tan \alpha \]
B) \[\mu >\frac{1}{2}\tan \alpha \]
C) \[\mu <\tan \alpha \]
D) \[\mu >\tan \alpha \]
Correct Answer: A
Solution :
For rotational equilibrium, net torque is 0. Taking torque about the center of Disc,\[Tr=fr\]or \[T=f.\] For slipping \[T+f<mg\,\sin \alpha \] or \[2f<mg\sin \alpha \] or \[2\mu \,mg\,\cos \alpha <mg\sin \alpha \] or \[\mu <\frac{1}{2}\tan \alpha \] Hence, the correction option is [a].You need to login to perform this action.
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