A) 51.96 N
B) 40 N
C) 28 N
D) 54.8 N
Correct Answer: B
Solution :
Limiting friction \[={{f}_{L}}=\mu \,mg\,\cos {{30}^{o}}=51.96\,N\]But \[mg\sin {{30}^{o}}<{{f}_{L}},\]so friction is static in nature and the block it not moving. Therefore, \[F=mg\sin {{30}^{o}}=40N.\] Hence, the correction option is [b].You need to login to perform this action.
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