Identify the product in the reaction\[PhC\equiv CMe\xrightarrow{{{H}_{3}}{{O}^{+}},H{{g}^{2+}}}\]
A)\[PhCOC{{H}_{2}}C{{H}_{3}}\]
B)\[PhC{{H}_{2}}C{{H}_{2}}CHO\]
C)\[PhCOCOMe\]
D)\[PhC{{H}_{2}}COC{{H}_{3}}\]
Correct Answer:
A
Solution :
Due to higher stability of this cation \[[Ph-\overset{\oplus }{\mathop{C}}\,=CMe]\]than methyl cation, the\[-O{{H}^{o-}}\] will attack on the benzylic cation. \[\therefore \]\[PhCOC{{H}_{2}}C{{H}_{3}}\] would be the major product. Hence, the correct option is [a].