• # question_answer Consider the situation shown in the figure. The capacitor A has a charge q on it whereas B is uncharged, The charge appearing on the capacitor B a long time after the switch is closed is A)  0                                B)  $\frac{q}{2}$C)  q                                D)  2q

Solution :

The negative charge on the right plate of capacitor A will be attracted by the positive charge on its left plate and hence, charge will not flow to capacitor B. Hence, the correction option is .

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