A) \[\frac{2T}{\sqrt{5}}\]
B) \[\left( \frac{\sqrt{5T}}{2} \right)\]
C) \[\frac{\sqrt{5}}{(2T)}\]
D) \[\frac{2}{\sqrt{5T}}\]
Correct Answer: A
Solution :
Let the new time period be T? The effective value of g for the accelerating lift will be \[g+g/4=5g/4\] \[T=2\pi \sqrt{\frac{\ell }{g}}\]and \[T'=2\pi \sqrt{\frac{\ell }{\frac{5g}{4}}}\] \[\therefore \] \[\frac{T'}{T}=\sqrt{\frac{4}{5}}=\frac{2}{\sqrt{5}}\]or \[T'=\frac{2T}{\sqrt{5}}\] Hence, the correction option is [a].
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