A) \[\frac{2g}{3}\]and\[\frac{mg}{3}\]
B) \[g\]and \[\frac{mg}{2}\]
C) \[\frac{g}{3}\]and \[\frac{mg}{2}\]
D) \[\frac{g}{2}\]and\[\frac{mg}{3}\]
Correct Answer: A
Solution :
Let a be the acceleration of the cylinder and \[\alpha \]be its angular acceleration. Invoking \[\tau =I\alpha \]about the center of the cylinder, we getYou need to login to perform this action.
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