• # question_answer $CuS{{O}_{4}}$and KCN reacts to produce A) $K[Cu{{(CN)}_{6}}]$B) $CuCN$C) $CuC{{N}_{2}}$D) ${{K}_{3}}[Cu{{(CN)}_{4}}]$

$2CuS{{O}_{4}}+10KCN\to \underset{\text{Potassium}\,\text{cuprocyanide}}{\mathop{2{{K}_{3}}[Cu{{(CN)}_{4}}]}}\,+2{{K}_{2}}S{{O}_{4}}$ Hence, the correct option is [d].