A) PV
B) \[P{{V}^{2}}\]
C) \[{{P}^{2}}V\]
D) \[\frac{P}{V}\]
Correct Answer: B
Solution :
From the principle of homogeneity, the dimensions of \[\frac{a}{{{V}^{2}}}\]must be the same as those of P, i.e., Dimensions of \[\frac{a}{{{V}^{2}}}=\] dimensions of P \[\therefore \] dimensions of a = dimension of \[P{{V}^{2}}.\] Hence, the correction option is [b].You need to login to perform this action.
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