A) 2.329 MeV
B) 3.298 MeV
C) 12.98 MeV
D) 5.478 MeV
Correct Answer: A
Solution :The sum of the masses of product = 29.9738 + 1.0078 = 30.9816 amu. The sum of the masses of reactants = 26.9815 + 4.0026 = 30.9841 amu. Difference in their masses \[(\Delta \Mu )\] = 30.9816 - 30.9841 = -0.0025 amu. Here the value of Q is +ve. So \[Q=+0.0025\times 931.5\] = +2.329 MeV Hence, the correct option is [a].
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