• # question_answer The correct decreasing order of basic strength is A) $P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}>N{{H}_{3}}$B) $~N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}$C) $As{{H}_{3}}>Sb{{H}_{3}}\text{ }>P{{H}_{3}}>N{{H}_{3}}$D) $Sb{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}>N{{H}_{3}}$

Solution :

As the basic strength of hydride decreases while on moving down the group so the correct order is as follows: $N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}$ Hence, the correct option is [b].

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