A) 12 cm
B) 30 cm
C) 50 cm
D) 60 cm
Correct Answer: C
Solution :
This is possible when the rays are incident on the mirror normally, i,e., the image by the lens is formed at the center of curvature of the mirror. Now, \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\]or \[\frac{1}{20}=\frac{1}{v}+\frac{1}{-30}\] or\[v=60\]From the figure, the distance of mirror from lens, \[LM=LC-MC=60-10=50\text{ }cm.\]Hence, the correction option is [c].You need to login to perform this action.
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