A) -312 J
B) -213 J
C) -321 J
D) -123 J
Correct Answer: B
Solution :
\[w=--{{V}_{1}}\int_{{}}^{{}}{{{V}_{2}}.PdV=-P({{V}_{2}}-{{V}_{1}})}\] \[W=-(1atm)(20-10)=-10\,d{{m}^{3}}\,\text{atm}\text{.}\] \[=-10\,d{{m}^{3}}\times \frac{8.314\,J{{K}^{-1}}\,mo{{l}^{-1}}}{0.08206\,d{{m}^{3}}{{K}^{-1}}mo{{l}^{-1}}}\] \[=-1013\,J.\] According to the first law of thermodynamics \[\Delta U=q+w\] \[=800+(-1013=-213\,J)\] Hence, the correct option is [b].You need to login to perform this action.
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