A) Z = 6
B) Z = 4
C) Z = 11
D) Z = 44
Correct Answer: A
Solution :
For \[{{K}_{a}}X-Ray\frac{1}{\lambda }\propto {{(Z-1)}^{2}}\] \[\Rightarrow \]\[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}={{\left( \frac{{{Z}_{1}}-1}{Z-1} \right)}^{2}}\Rightarrow \frac{\lambda }{4\lambda }={{\left( \frac{{{Z}_{2}}-1}{{{Z}_{1}}-1} \right)}^{2}}\] \[\therefore \] \[{{Z}_{2}}=6\] Hence, the correction option is (a).You need to login to perform this action.
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