A) 400 nm
B) 450 nm
C) 500 nm
D) 600 nm
Correct Answer: D
Solution :
Distance between second dark fringe and central fringe \[{{x}_{2}}=\frac{(2n-1)D\lambda }{2d}\] \[\therefore \]\[\lambda =\frac{2d{{x}_{2}}}{(2n-1)d}=\frac{2(0.9\times {{10}^{-3}})\times {{10}^{-3}}}{(2\times 2-1)\times 1}=6\times {{10}^{-7}}\,m\] \[=600\,nm.\] Hence, the correction option is (d).You need to login to perform this action.
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