A) R
B) 2R
C) 3R
D) 4R
Correct Answer: B
Solution :
Initially \[x-\]coordinate of center of mass is: \[{{x}_{1}}=\frac{(4M)(0)+M(5R)}{4M+M}=R\] (1) Let \[{{x}_{0}}\]be the x-coordinate of shell when the small sphere reaches the other extreme position. Then finally c-coordinate of center of mass is \[{{x}_{f}}=\frac{4M({{x}_{0}})+M({{x}_{0}}-5R)}{4M+M}\] \[={{x}_{0}}-R\] (2) All the surfaces are smooth, therefore, center of mass will not move in \[x-\]direction \[\therefore \]\[{{x}_{1}}={{x}_{f}}\] or \[R={{x}_{0}}-R\] or \[{{x}_{0}}=2R\] Hence, the correction option is (b).You need to login to perform this action.
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