A) \[{{60}^{o}}\]
B) \[{{15}^{o}}\]
C) \[{{30}^{o}}\]
D) \[{{45}^{o}}\]
Correct Answer: A
Solution :
Conserving the horizontal component component of the projectile, in context to figure, we get \[v=u\cos \theta \] \[\frac{u}{2}=u\cos \theta \Rightarrow \cos \theta =\frac{1}{2}\]or \[\theta ={{60}^{o}}\] Hence, the correction option is (a).You need to login to perform this action.
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