A) -113 J
B) +113 J
C) -213 J
D) +313 J
Correct Answer: C
Solution :
We know that\[W=-\int\limits_{{{V}_{1}}}^{{{V}_{2}}}{PdV}\] Here, P = constant. So, \[W=-P({{V}_{2}}-{{V}_{1}})\] \[W=-(1)(20-10)=-10\,d{{m}^{3}}\,\text{atm}\] \[=-10\,d{{m}^{3}}\times \frac{8.314\,J{{K}^{-1}}\,mo{{l}^{-1}}}{0.08206\,d{{m}^{3}}\,mo{{l}^{-1}}}\] \[W=-1013\,J.\] Now using the first law of thermodynamics, \[\Delta U=Q+W=80\,J+(-1013)=-213\,J.\] Hence, the correct option is (c).You need to login to perform this action.
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